705. Design HashSet

Easy


Design a HashSet without using any built-in hash table libraries.

Implement MyHashSet class:

  • void add(key) Inserts the value key into the HashSet.
  • bool contains(key) Returns whether the value key exists in the HashSet or not.
  • void remove(key) Removes the value key in the HashSet. If key does not exist in the HashSet, do nothing.

 

Example 1:

Input
["MyHashSet", "add", "add", "contains", "contains", "add", "contains", "remove", "contains"]
[[], [1], [2], [1], [3], [2], [2], [2], [2]]
Output
[null, null, null, true, false, null, true, null, false]

Explanation
MyHashSet myHashSet = new MyHashSet();
myHashSet.add(1);      // set = [1]
myHashSet.add(2);      // set = [1, 2]
myHashSet.contains(1); // return True
myHashSet.contains(3); // return False, (not found)
myHashSet.add(2);      // set = [1, 2]
myHashSet.contains(2); // return True
myHashSet.remove(2);   // set = [1]
myHashSet.contains(2); // return False, (already removed)

 

Constraints:

  • 0 <= key <= 106
  • At most 104 calls will be made to add, remove, and contains.




 class Bucket:
    def __init__(self):
        #self.list = []
        self.head = Node(0) # pseudo Head

    def add(self, key):
        if not self.contains(key):
            #self.list.append(key)
            self.head.next = Node(key, self.head.next)


    def remove(self, key):
        # for i in self.list:
        #     if i == key:
        #         self.list.remove(i)
        #         break
        prev = self.head
        current = self.head.next
        while current is not None:
            if current.val == key:
                prev.next = current.next
                return
            prev = current
            current = current.next

    def contains(self, key):
        # for i in self.list:
        #     if i == key:
        #         return True
        # return False
        current = self.head.next
        while current is not None:
            if current.val == key:
                return True
            current = current.next
        return False

class Node:
    def __init__(self, val, next_node = None):
        self.val = val
        self.next = next_node

class MyHashSet:

    def __init__(self):
        self.key = 769
        self.buckets = [Bucket() for i in range(self.key)]


    def add(self, key: int) -> None:
        hash_key = key%self.key
        self.buckets[hash_key].add(key)


    def remove(self, key: int) -> None:
        hash_key = key%self.key
        self.buckets[hash_key].remove(key)


    def contains(self, key: int) -> bool:
        hash_key = key%self.key
        return self.buckets[hash_key].contains(key)



# Your MyHashSet object will be instantiated and called as such:
# obj = MyHashSet()
# obj.add(key)
# obj.remove(key)
# param_3 = obj.contains(key)

Random Note


(k := next(iter(d)), d.pop(k)) will remove the leftmost (first) item (if it exists) from a dict object. And if you want to remove the right most/recent value from the dict

d.popitem()