Design a data structure that accepts a stream of integers and checks if it has a pair of integers that sum up to a particular value.

Implement the TwoSum class:

  • TwoSum() Initializes the TwoSum object, with an empty array initially.
  • void add(int number) Adds number to the data structure.
  • boolean find(int value) Returns true if there exists any pair of numbers whose sum is equal to value, otherwise, it returns false.

 

Example 1:

Input
["TwoSum", "add", "add", "add", "find", "find"]
[[], [1], [3], [5], [4], [7]]
Output
[null, null, null, null, true, false]

Explanation
TwoSum twoSum = new TwoSum();
twoSum.add(1);   // [] --> [1]
twoSum.add(3);   // [1] --> [1,3]
twoSum.add(5);   // [1,3] --> [1,3,5]
twoSum.find(4);  // 1 + 3 = 4, return true
twoSum.find(7);  // No two integers sum up to 7, return false

 

Constraints:

  • -105 <= number <= 105
  • -231 <= value <= 231 - 1
  • At most 104 calls will be made to add and find.




 class TwoSum:

    def __init__(self):
        self.s = {}

    def add(self, number: int) -> None:
        self.s[number] = self.s.get(number, 0)+1

    def find(self, value: int) -> bool:

        for n in self.s.keys():
            req_digit = value - n

            if n!= req_digit:
                if req_digit in self.s:
                    return True
            else:
                if self.s[req_digit]>1:

                    return True
        return False



# Your TwoSum object will be instantiated and called as such:
# obj = TwoSum()
# obj.add(number)
# param_2 = obj.find(value)

Random Note


leetcode problem 287. Find the Duplicate Number has 7 solving approach. WOW!!!