1507. Reformat Date

Easy

Given a date string in the form Day Month Year, where:

Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

YYYY denotes the 4 digit year.
MM denotes the 2 digit month.
DD denotes the 2 digit day.

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

Constraints:

The given dates are guaranteed to be valid, so no error handling is necessary.

 class Solution:
    def reformatDate(self, date: str) -> str:

        months = {'Jan':'01', 'Feb':'02', 'Mar':'03', 'Apr':'04','May':'05', 'Jun':'06', 'Jul':'07', 'Aug':'08','Sep':'09','Oct':'10','Nov':'11', 'Dec':'12'}    


        dd = date.split()    
        month = months[dd[1]]
        day = dd[0][0:-2]

        if len(day) == 1:
            day = '0'+day

        final_output = dd[2]+"-" + month+"-"+day
        return final_output

1507. Reformat Date

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