Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, and /. Each operand may be an integer or another expression.
Note that division between two integers should truncate toward zero.
It is guaranteed that the given RPN expression is always valid. That means the expression would always evaluate to a result, and there will not be any division by zero operation.
Example 1:
Input: tokens = ["2","1","+","3","*"] Output: 9 Explanation: ((2 + 1) * 3) = 9
Example 2:
Input: tokens = ["4","13","5","/","+"] Output: 6 Explanation: (4 + (13 / 5)) = 6
Example 3:
Input: tokens = ["10","6","9","3","+","-11","*","/","*","17","+","5","+"] Output: 22 Explanation: ((10 * (6 / ((9 + 3) * -11))) + 17) + 5 = ((10 * (6 / (12 * -11))) + 17) + 5 = ((10 * (6 / -132)) + 17) + 5 = ((10 * 0) + 17) + 5 = (0 + 17) + 5 = 17 + 5 = 22
Constraints:
1 <= tokens.length <= 104tokens[i]is either an operator:"+","-","*", or"/", or an integer in the range[-200, 200].
class Solution:
def result(self, n1, n2, op):
if op == '+':
return n1+n2
elif op == '-':
return n1-n2
elif op == '*':
return n1*n2
else:
return int(n1 / n2)
def evalRPN(self, tokens: List[str]) -> int:
stack = []
operators = ('+', '-', '*', '/')
r = None
for item in tokens:
if item not in operators:
stack.append(item)
else:
val2 = stack.pop()
val1 = stack.pop()
r = self.result(int(val1), int(val2), item)
#print(r)
#print(val1, item, val2, r)
stack.append(r)
return int(stack.pop())