66. Plus One

Easy


You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0's.

Increment the large integer by one and return the resulting array of digits.

 

Example 1:

Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].

Example 2:

Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].

Example 3:

Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].

 

Constraints:

  • 1 <= digits.length <= 100
  • 0 <= digits[i] <= 9
  • digits does not contain any leading 0's.




 class Solution:
    def plusOne(self, digits: List[int]) -> List[int]:

        digits = map(str, digits)
        number = str("".join(digits))
        result = int(number)+1
        digits = list(map(int, str(result)))

        return digits

Random Note


time.perf_counter() always returns the float value of time in seconds. while pref_counter_ns() always gives the integer value of time in nanoseconds.


t1_start = perf_counter()
t1_stop = perf_counter()
print("Elapsed time:", t1_stop, t1_start)