Medium
Design your implementation of the linked list. You can choose to use a singly or doubly linked list.
A node in a singly linked list should have two attributes: val and next. val is the value of the current node, and next is a pointer/reference to the next node.
If you want to use the doubly linked list, you will need one more attribute prev to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement the MyLinkedList class:
MyLinkedList()Initializes theMyLinkedListobject.int get(int index)Get the value of theindexthnode in the linked list. If the index is invalid, return-1.void addAtHead(int val)Add a node of valuevalbefore the first element of the linked list. After the insertion, the new node will be the first node of the linked list.void addAtTail(int val)Append a node of valuevalas the last element of the linked list.void addAtIndex(int index, int val)Add a node of valuevalbefore theindexthnode in the linked list. Ifindexequals the length of the linked list, the node will be appended to the end of the linked list. Ifindexis greater than the length, the node will not be inserted.void deleteAtIndex(int index)Delete theindexthnode in the linked list, if the index is valid.
Example 1:
Input ["MyLinkedList", "addAtHead", "addAtTail", "addAtIndex", "get", "deleteAtIndex", "get"] [[], [1], [3], [1, 2], [1], [1], [1]] Output [null, null, null, null, 2, null, 3] Explanation MyLinkedList myLinkedList = new MyLinkedList(); myLinkedList.addAtHead(1); myLinkedList.addAtTail(3); myLinkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 myLinkedList.get(1); // return 2 myLinkedList.deleteAtIndex(1); // now the linked list is 1->3 myLinkedList.get(1); // return 3
Constraints:
0 <= index, val <= 1000- Please do not use the built-in LinkedList library.
- At most
2000calls will be made toget,addAtHead,addAtTail,addAtIndexanddeleteAtIndex.
class ListNode:
def __init__(self, val, next = None, prev = None):
self.val = val
self.next = next
self.prev = prev
class MyLinkedList:
def __init__(self):
self.sentinel_head = ListNode(0)
self.sentinel_tail = ListNode(0)
self.sentinel_head.next = self.sentinel_tail
self.sentinel_tail.prev = self.sentinel_head
self.size = 0
def show(self):
node = self.sentinel_head.next
for _ in range(self.size):
print(node.val, end=" ")
node = node.next
print()
def addAtHead(self, value):
new_head = ListNode(value, self.sentinel_head.next, self.sentinel_head)
# updating old head ponters
self.sentinel_head.next.prev = new_head
self.sentinel_head.next = new_head
self.size+=1
def addAtTail(self, value):
new_tail = ListNode(value, self.sentinel_tail, self.sentinel_tail.prev)
self.sentinel_tail.prev.next = new_tail
self.sentinel_tail.prev = new_tail
self.size+=1
def addAtIndex(self, index, value):
if index > self.size:
return
if index < 0:
index = 0
# decide shortest node index position
if index < self.size-index: # head is closer
pred = self.sentinel_head
for _ in range(index):
pred = pred.next
succ = pred.next
# adding node
new_node = ListNode(value, succ, pred)
pred.next = new_node
succ.prev = new_node
else: # tail is closer
succ = self.sentinel_tail
for _ in range(self.size-index):
succ = succ.prev
pred = succ.prev
# new node
new_node = ListNode(value, succ, pred)
succ.prev = new_node
pred.next = new_node
self.size+=1
def deleteAtIndex(self, index):
if index < 0 or index >= self.size:
return
# find predecessor and successor of the node to be deleted
if index < self.size - index:
pred = self.sentinel_head
for _ in range(index):
pred = pred.next
succ = pred.next.next
else:
succ = self.sentinel_tail
for _ in range(self.size - index - 1):
succ = succ.prev
pred = succ.prev.prev
# delete pred.next
self.size -= 1
pred.next = succ
succ.prev = pred
def get(self, index):
# validating index
if index < 0 or index > self.size-1:
return -1
if index < (self.size//2): # head
node = self.sentinel_head
for _ in range(index+1):
node = node.next
return node.val
else:
node = self.sentinel_tail
for _ in range(self.size-index):
node = node.prev
return node.val