Given a directed acyclic graph (DAG) of n nodes labeled from 0 to n - 1, find all possible paths from node 0 to node n - 1 and return them in any order.
The graph is given as follows: graph[i] is a list of all nodes you can visit from node i (i.e., there is a directed edge from node i to node graph[i][j]).
Example 1:
Input: graph = [[1,2],[3],[3],[]] Output: [[0,1,3],[0,2,3]] Explanation: There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.
Example 2:
Input: graph = [[4,3,1],[3,2,4],[3],[4],[]] Output: [[0,4],[0,3,4],[0,1,3,4],[0,1,2,3,4],[0,1,4]]
Constraints:
n == graph.length2 <= n <= 150 <= graph[i][j] < ngraph[i][j] != i(i.e., there will be no self-loops).- All the elements of
graph[i]are unique. - The input graph is guaranteed to be a DAG.
class Solution:
def allPathsSourceTarget(self, graph: List[List[int]]) -> List[List[int]]:
target = len(graph)-1
result = []
def path_finder(current, path):
if current == target:
result.append(path[:])
return
for node in graph[current]:
path.append(node)
path_finder(node, path)
path.pop()
path = [0]
path_finder(0, path)
return result