Medium
A peak element is an element that is strictly greater than its neighbors.
Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple peaks, return the index to any of the peaks.
You may imagine that nums[-1] = nums[n] = -∞. In other words, an element is always considered to be strictly greater than a neighbor that is outside the array.
You must write an algorithm that runs in O(log n) time.
Example 1:
Input: nums = [1,2,3,1] Output: 2 Explanation: 3 is a peak element and your function should return the index number 2.
Example 2:
Input: nums = [1,2,1,3,5,6,4] Output: 5 Explanation: Your function can return either index number 1 where the peak element is 2, or index number 5 where the peak element is 6.
Constraints:
1 <= nums.length <= 1000-231 <= nums[i] <= 231 - 1nums[i] != nums[i + 1]for all validi.
class Solution:
def findPeakElement(self, nums: List[int]) -> int:
if len(nums) == 1:
return 0
for i in range(len(nums)-1):
if nums[i]>nums[i+1]:
return i
return len(nums)-1