2419. Longest Subarray With Maximum Bitwise AND
Medium
You are given an integer array nums of size n.
Consider a non-empty subarray from nums that has the maximum possible bitwise AND.
- In other words, let
kbe the maximum value of the bitwise AND of any subarray ofnums. Then, only subarrays with a bitwise AND equal tokshould be considered.
Return the length of the longest such subarray.
The bitwise AND of an array is the bitwise AND of all the numbers in it.
A subarray is a contiguous sequence of elements within an array.
Example 1:
Input: nums = [1,2,3,3,2,2] Output: 2 Explanation: The maximum possible bitwise AND of a subarray is 3. The longest subarray with that value is [3,3], so we return 2.
Example 2:
Input: nums = [1,2,3,4] Output: 1 Explanation: The maximum possible bitwise AND of a subarray is 4. The longest subarray with that value is [4], so we return 1.
Constraints:
1 <= nums.length <= 1051 <= nums[i] <= 106
class Solution:
def longestSubarray(self, nums: List[int]) -> int:
# count = 1
# max_num = nums[0]
# mm = 1
# sub_array = True
# for i, num in enumerate(nums[1:]):
# if num == max_num and sub_array:
# count+=1
# mm = max(count, mm)
# #sub_array = False
# #print(count)
# elif num >= max_num:
# if num > max_num:
# mm = 1
# max_num = num
# sub_array = True
# count = 1
# else:
# sub_array = False
# return mm
max_num = max(nums)
max_count = 0
for x, y in groupby(nums):
if x == max_num:
max_count = max(max_count, len(list(y)))
return max_count