Given an array of strings strs, group the anagrams together. You can return the answer in any order.

An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.

 

Example 1:

Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]

Example 2:

Input: strs = [""]
Output: [[""]]

Example 3:

Input: strs = ["a"]
Output: [["a"]]

 

Constraints:

  • 1 <= strs.length <= 104
  • 0 <= strs[i].length <= 100
  • strs[i] consists of lowercase English letters.




 class Solution:
    def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
        m = {}
        for item in strs:
            s = ''.join(sorted(item))

            if s not in m:
                m[s] = [item]
            else:
                m[s].append(item)

        return list(m.values())

Random Note


(k := next(iter(d)), d.pop(k)) will remove the leftmost (first) item (if it exists) from a dict object. And if you want to remove the right most/recent value from the dict

d.popitem()