Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

  1. Each row must contain the digits 1-9 without repetition.
  2. Each column must contain the digits 1-9 without repetition.
  3. Each of the nine 3 x 3 sub-boxes of the grid must contain the digits 1-9 without repetition.

Note:

  • A Sudoku board (partially filled) could be valid but is not necessarily solvable.
  • Only the filled cells need to be validated according to the mentioned rules.

 

Example 1:

Input: board = 
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: true

Example 2:

Input: board = 
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.

 

Constraints:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] is a digit 1-9 or '.'.




 class Solution:
    def isValidSudoku(self, board: List[List[str]]) -> bool:

        for rows in board:
            h = set()
            for value in rows:
                if value != ".":

                    if value in h:
                        #print("1")
                        return False
                    else:
                        h.add(value)           



        for start in [0,3,6]:
            for end in [0,3,6]:
                x = set()
                for i in range(start, start+3):
                    for j in range(end, end+3):
                        if board[i][j] != ".":

                            if board[i][j] in x:
                                return False
                            else:
                                x.add(board[i][j])



        for i in range(9):
            h = set()
            for j in range(9):
                if board[j][i] != ".":
                    if board[j][i] in h:
                        return False
                    else:
                        h.add(board[j][i])    

        return True

Random Note


Pythonic Time Complexity Wiki

Important to remember