2419. Longest Subarray With Maximum Bitwise AND

Medium


You are given an integer array nums of size n.

Consider a non-empty subarray from nums that has the maximum possible bitwise AND.

  • In other words, let k be the maximum value of the bitwise AND of any subarray of nums. Then, only subarrays with a bitwise AND equal to k should be considered.

Return the length of the longest such subarray.

The bitwise AND of an array is the bitwise AND of all the numbers in it.

A subarray is a contiguous sequence of elements within an array.

 

Example 1:

Input: nums = [1,2,3,3,2,2]
Output: 2
Explanation:
The maximum possible bitwise AND of a subarray is 3.
The longest subarray with that value is [3,3], so we return 2.

Example 2:

Input: nums = [1,2,3,4]
Output: 1
Explanation:
The maximum possible bitwise AND of a subarray is 4.
The longest subarray with that value is [4], so we return 1.

 

Constraints:

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 106




 class Solution:
    def longestSubarray(self, nums: List[int]) -> int:

#         count = 1
#         max_num = nums[0] 
#         mm = 1
#         sub_array = True

#         for i, num in enumerate(nums[1:]):

#             if num == max_num and sub_array:
#                 count+=1
#                 mm = max(count, mm)
#                 #sub_array = False
#                 #print(count)

#             elif num >= max_num:
#                 if num > max_num:
#                     mm = 1
#                 max_num = num
#                 sub_array = True
#                 count = 1

#             else:
#                 sub_array = False

#         return mm

        max_num = max(nums)
        max_count = 0
        for x, y in groupby(nums):
            if x == max_num:
                max_count = max(max_count, len(list(y)))
        return max_count

Random Note


Amortized time is the way to express the time complexity when an algorithm has the very bad time complexity only once in a while besides the time complexity that happens most of time. Good example would be an ArrayList which is a data structure that contains an array and can be extended.