Given an array of integers nums, sort the array in ascending order and return it.
You must solve the problem without using any built-in functions in O(nlog(n)) time complexity and with the smallest space complexity possible.
Example 1:
Input: nums = [5,2,3,1] Output: [1,2,3,5] Explanation: After sorting the array, the positions of some numbers are not changed (for example, 2 and 3), while the positions of other numbers are changed (for example, 1 and 5).
Example 2:
Input: nums = [5,1,1,2,0,0] Output: [0,0,1,1,2,5] Explanation: Note that the values of nums are not necessairly unique.
Constraints:
1 <= nums.length <= 5 * 104-5 * 104 <= nums[i] <= 5 * 104
class Solution:
def sortArray(self, nums: List[int]) -> List[int]:
heapq.heapify(nums)
return [heapq.heappop(nums) for _ in range(len(nums))]